Returns the USDA texture class name for each row based on the sand, silt,
and clay fractions. Inputs are expected in per-cent (0–100) and must sum
to approximately 100.
Usage
classify_texture(sand, silt, clay, tol = 1)
Arguments
- sand
Numeric vector: sand content (%).
- silt
Numeric vector: silt content (%).
- clay
Numeric vector: clay content (%).
- tol
Tolerance for the 100 % sum check (default 1.0).
Value
Character vector of USDA texture class names. Returns NA
for rows where values are missing or do not sum to approximately 100.
Examples
classify_texture(sand = c(70, 20, 10, 40),
silt = c(15, 50, 30, 40),
clay = c(15, 30, 60, 20))
#> [1] "Sandy Loam" "Silty Clay Loam" "Clay" "Loam"
